Download Communication Systems Engineering - Solutions Manual by John G. Proakis PDF

By John G. Proakis

Thorough assurance of simple electronic communique approach rules guarantees that readers are uncovered to all easy suitable issues in electronic verbal exchange process layout. using CD participant and JPEG photograph coding typical as examples of platforms that hire smooth conversation rules permits readers to narrate the idea to useful platforms. Over one hundred eighty worked-out examples in the course of the ebook aids readers in knowing uncomplicated techniques. Over 480 difficulties concerning purposes to functional structures comparable to satellite tv for pc communications platforms, ionospheric channels, and cellular radio channels provides readers considerable chance to perform the recommendations they've got simply realized. With an emphasis on electronic communications, Communication platforms Engineering, moment Edition introduces the elemental rules underlying the research and layout of communique platforms. additionally, this e-book offers an exceptional advent to analog communications and a overview of vital mathematical origin subject matters. New fabric has been additional on instant verbal exchange systems—GSM and CDMA/IS-94; faster codes and iterative interpreting; multicarrier (OFDM) platforms; a number of antenna platforms. comprises thorough assurance of uncomplicated electronic conversation approach principles—including resource coding, channel coding, baseband and provider modulation, channel distortion, channel equalization, synchronization, and instant communications. contains easy insurance of analog modulation similar to amplitude modulation, section modulation, and frequency modulation in addition to demodulation equipment. to be used as a reference for electric engineers for all uncomplicated suitable subject matters in electronic communique process layout.

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Example text

5 = 236 2 2 PAM = The bandwidth of the signal is WAM = 2W = 20000 Hz. 25 1) The maximum phase deviation of the PM signal is ∆φmax = kp max[|m(t)|] = kp The phase of the FM modulated signal is t φ(t) = 2πkf      t m(τ )dτ = 2πkf −∞ 2πkf 0t τ dτ m(τ )dτ 0 = πkf t2 0≤t<1 t πkf + 2πkf 1 dτ = πkf + 2πkf (t − 1) 1≤t<2 = t  πk + 2πk − 2πk dτ = 3πk − 2πk (t − 2) 2≤t<3  f f f 2 f f   3≤t πkf 58 The maximum value of φ(t) is achieved for t = 2 and is equal to 3πkf . Thus, the desired relation between kp and kf is kp = 3πkf 2) The instantaneous frequency for the PM modulated signal is fi (t) = fc + d 1 d 1 φ(t) = fc + kp m(t) 2π dt 2π dt For the m(t) given in Fig.

2. . . . . . r. fc −103 fc +103 −π r. . . . . . . . 2. . . . . . . . . r. 2) The average power in the carrier is Pcarrier = 1002 A2c = = 5000 2 2 The power in the sidebands is Psidebands = 502 502 2502 2502 + + + = 65000 2 2 2 2 3) The message signal can be written as m(t) = sin(2π103 t) + 5 cos(2π2 × 103 t) = −10 sin(2π103 t) + sin(2π103 t) + 5 As it is seen the minimum value of m(t) is −6 and is achieved for sin(2π103 t) = −1 or t = 3 + 1013 k, with k ∈ Z. Hence, the modulation index is α = 6.

Invert X(f − 2T1 s ) and multiply the resultant Ts Π( f2W signal by e−j2πW t . 39 1) The linear interpolation system can be viewed as a linear filter where the sampled signal x(t) ∞ n=−∞ δ(t − nTs ) is passed through the filter with impulse response h(t) =  t   1 + Ts   1− 0 t Ts −Ts ≤ f ≤ 0 0 ≤ f ≤ Ts otherwise To see this write ∞ x1 (t) = x(t) ∞ δ(t − nTs ) h(t) = n=−∞ x(nTs )h(t − nTs ) n=−∞ Comparing this with the interpolation formula in the interval [nTs , (n + 1)Ts ] t − nTs (x((n + 1)Ts ) − x(nTs )) Ts t − nTs t − (n + 1)Ts + x((n + 1)Ts ) 1 + = x(nTs ) 1 − Ts Ts = x(nTs )h(t − nTs ) + x((n + 1)Ts )h(t − (n + 1)Ts ) x1 (t) = x(nTs ) + 31 we observe that h(t) does not extend beyond [−Ts , Ts ] and in this interval its form should be the one described above.

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